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Calculation of 0x29

m(x) = 0x11b = 100011011 = x^8 + x^4 + x^3 + x + 1
a(x) = 0x29 =  00101001 = x^5 + x^3 + 1
m(x) = (x^3 + x) * a(x) + (1)

Calculation of 0x29-1 in the finite field GF(28)

00000001 = 00000001 * 100011011 + 00001010 * 101001
00000000 = 00101001 * 100011011 + 100011011 * 101001

a-1(x) = x^3 + x = 00001010 = 0x0a

The calculation of 0x29-1 is made with the Extended Euclidean algorithm. Instead of normal division and multiplication you need to use Polynomialdivision and Polynomialmultiplication.


Affine transformation over GF(2)
           1 0 0 0 1 1 1 1      0     1     1
1 1 0 0 0 1 1 1 1 1 0
1 1 1 0 0 0 1 1 0 0 1
1 1 1 1 0 0 0 1 1 0 0
SBOX(29) = 1 1 1 1 1 0 0 0 * 0 + 0 = 0
0 1 1 1 1 1 0 0 0 1 1
0 0 1 1 1 1 1 0 0 1 0
0 0 0 1 1 1 1 1 0 0 1


SBOX(29) = 10100101 = a5

For more information see FIPS 197.



Implemented by bachph [at] philba [dot] com